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Given a fibonacci sequence where $f(n)=f(n-1)+f(n-2) for \space n\ge 2
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View question - The function f(n) = 3f(n-2) - 2f(n-1), where f(2) = 3
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If f(1) = 1 and f(n+1) = 2f(n) + 1 if n≥1, then f(n) is equal to 2^n+1b
F N F N-1 +f N-3
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